http://www.perlmonks.org?node_id=1017306


in reply to Using special characters in left part of a regex match?

$var[$j] =~ s/\.\.\./\.\+/g;

The right half of an s/// substitution is not a regex, but a mere string. So if you want to construct .+ in the replacement, you need to write it as .+ and not at \.\+.