in reply to Re: Why Perl boolean expression sometimes treated as lvalue?
in thread Why Perl boolean expression sometimes treated as lvalue?
perlop perlop perlop , precedence is everything :)
$ perl -E " print ( 1 && 2 ) 2 $ perl -E " sub ff { ++$_[0] } my($f,$a)=(1,5); ff( $f && $a ); say $f +; say $a; " 1 6
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