Re: die silently in an eval block while using alarm

[andal]

in reply to die silently in an eval block while using alarm

I can't really see, how "die" in your code could produce any output. It is called by ALRM signal handler inside of eval, so the output of "die" is saved in $@ and not printed anywhere. If you get some output, then it comes from somewhere else. Check for example this code

my $ch;

eval{
    $SIG{ALRM} = sub{
        die "Waiting finished\n";
    };
    alarm(10);
    $ch = <STDIN>;
    alarm(0);
};

if($@)
{
    print "Timeout happened\n";
}
else
{
    print "Got $ch";
}

You'll never see "Waiting finished" because it is stored in $@ variable and the code does not print it.

[gg48gg]

Thanks for the reply. I agree, I shouldn't have any output from die. Is it possible that I get output from the result of die? I can't explain the behavior, I can just observe it. Thanks for the example code, I will study it for a bit.

[andal]

What do you mean by "result of die"? "die" never returns, so there is no "result" returned.

Search for the problem somewhere else. It has nothing to do with "die" in provided piece of code. Inside of eval "die" does not produce any output. Check your other "warn", "print", "write", or "die" outside of eval.