|Perl: the Markov chain saw|
Re^3: Program Design Around Threadsby BrowserUk (Pope)
|on Mar 06, 2013 at 07:38 UTC||Need Help??|
What is the point of the locks? The id's are unique, right? As far as I can tell, it doesn't matter if every thread--including the outputter--all modify the hash at the same time.
Primary reason is that getters add key/value pairs to the hash; and the outputter removes key/value pairs from the hash. These are substantive modifications to the hash structure.
It may be that Perl's internal locking is sufficient to ensure that the key cannot be seen before the value is also available, but if that is the case, the additional locking will incur very little overhead as it will be released at almost exactly the same time as the internal lock.
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