|There's more than one way to do things|
Re^5: Display tide based on time now.by Anonymous Monk
|on Mar 27, 2013 at 18:34 UTC||Need Help??|
Sounds like you've got a very straightforward algorithm laid out there. It is difficult to be both "greater" and "equal" at the same time, but I presume you meant to say "or".
You may have also noticed how repetitive it is, and that it can be reworded as a for loop, using N, and (N+1)%$numTidePoints