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Re^2: binary converter

by Jenda (Abbot)
on Apr 23, 2013 at 12:20 UTC ( #1030121=note: print w/ replies, xml ) Need Help??

in reply to Re: binary converter
in thread binary converter

The position shoul be digit :-)

In either case you do not need the index nor the ** operator.

my @digit = reverse split //, $bin; my $num = 0; for my $bit (@digit) { $num = $num * 2 + $bit; } print "\n$num\n";

Enoch was right!
Enjoy the last years of Rome.

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Re^3: binary converter
by Limbic~Region (Chancellor) on Apr 23, 2013 at 17:25 UTC
    Or digit should have been position.

    I wouldn't have written the code I did for myself - it was intended to be more instructional since the OP indicated not understanding the for loop. I guess I should have paid closer attention (updated now). Thanks!

    Cheers - L~R

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