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Re^2: scoping inside the loop

by Anonymous Monk
on May 17, 2013 at 18:36 UTC ( #1034006=note: print w/ replies, xml ) Need Help??

in reply to Re: scoping inside the loop
in thread scoping inside the loop

Thanks LanX.Understood but in second case which is a working condition $i's scope is in outer loop but how it got tucked in to inside loop.My understanding is if my is before a variable it's existence is strictly with in that boundary. In case 2 my is associated with $i so i think it only resides outside or where it is defined but i am confused how it got transported to loop.

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Re^3: scoping inside the loop
by LanX (Canon) on May 17, 2013 at 18:40 UTC
    No, up to the point that you declare an inner $i with my the outer one is used.

    No inner my $i means the outer one is everywhere available.

    These are universal rules for lexical variables in almost any language!

    Have a look at the scoping-article I linked.

    Cheers Rolf

    ( addicted to the Perl Programming Language)

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