perladdict has asked for the wisdom of the Perl Monks concerning the following question:
Hi Monks,
With the Below code i am trying to list directory content in windows OS, i am able to print the directory content.once after obtaining the subfolders in the directory, i wanted to create the zip for the subfolders like bk_20130520.zip
Output#!/usr/bin/perl print "Hellow World\n"; opendir(D,"C:\\xxx\\xxxx\dirname") or die "can't open the directory\n" +; my @folders = grep {(!/^\./) && (!/^\.\./)} readir(D); foreach (@folders) { $prefix = "bk"; Print "$_\n"; system("Zip $_ $prefix.$_"); }
The zip feature i have not used before in script,monks it would be a kind if you can guide me to get this zip created for the subfolders.Hello World 20130516 20130517 20130520 Zip Error: Nothing to do! <20130516.zip> Zip wanrning name not matched: 20130516
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Replies are listed 'Best First'. | |
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Re: After listing the folder in a directoy, i unable to zip the folders by using system command.
by marto (Cardinal) on May 21, 2013 at 13:42 UTC | |
Re: After listing the folder in a directoy, i unable to zip the folders by using system command.
by hdb (Monsignor) on May 21, 2013 at 14:27 UTC | |
Re: After listing the folder in a directoy, i unable to zip the folders by using system command.
by ww (Archbishop) on May 21, 2013 at 14:11 UTC | |
Re: After listing the folder in a directoy, i unable to zip the folders by using system command.
by Anonymous Monk on May 21, 2013 at 22:22 UTC |
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