Re: Why doesn't "my ($x) = @);" generate a syntax error?

in reply to Why doesn't "my ($x) = @);" generate a syntax error?

For any punctuation character x, if there is a magic variable called $x, then there must also be magic variables called @x and %x. That's an artefact of how current versions of the Perl parser work. So because the $) exists and does something useful, the @) variable must also exist (even if it does nothing useful!)

package Cow { use Moo; has name => (is => 'lazy', default => sub { 'Mooington' }) } say Cow->new->name

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Re^2: Why doesn't "my ($x) = @);" generate a syntax error? by Grimy (Pilgrim) on Jun 13, 2013 at 17:57 UTC
Correction: for any punctuation character x except '[' and '{', there exist global variables $x, @x and %x. Those variables are not necessarily magic, and their existence doesn't depend on the fact that $x does something useful. For example, none of $}, @} and %} are magic, yet they are all global variables.	[reply]
Re^3: Why doesn't "my ($x) = @);" generate a syntax error? by tobyink (Canon) on Jun 13, 2013 at 23:31 UTC
`$[`, `@[` and `%[` work (or at least they do in 5.18.0). If `${`, `@{` and `%{` were to work, that would break dereferencing. `package Cow { use Moo; has name => (is => 'lazy', default => sub { 'Mooington' }) } say Cow->new->name`	[reply] [d/l] [select]
Re^2: Why doesn't "my ($x) = @);" generate a syntax error? by zork42 (Monk) on Jun 13, 2013 at 06:57 UTC
I'd have never realised that. Thanks!	[reply]

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