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Re^4: Finding repeat sequences. (only regex)

by BrowserUk (Pope)
on Jun 18, 2013 at 20:21 UTC ( #1039652=note: print w/ replies, xml ) Need Help??


in reply to Re^3: Finding repeat sequences. (only regex)
in thread Finding repeat sequences.

Nice reversal of the logic and closer:

$s = 'aaaabaaaabaaaaabaaaab';; $s =~ /^((.*?).*?)\2*\1$/ and print "$2/$1";; a/aaaabaaaab

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Comment on Re^4: Finding repeat sequences. (only regex)
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Re^5: Finding repeat sequences. (only regex!)
by tye (Cardinal) on Jun 18, 2013 at 21:17 UTC

    I think I had \1 and \2 backward. Then you just have to disallow the trivial solution:

    $s = 'aaaabaaaabaaaaabaaaab'; $s =~ /^((.*?).*?)(?=.)\1*\2$/ and print "$2/$1";

    (Update: Dropped the unneeded () around \1 that I had introduced while debugging. You probably also need to change .*? to .* so you get the longest solution not the shortest.)

    - tye        

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