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Re^3: Wordfeud racks

by RichardK (Vicar)
on Jul 30, 2013 at 17:29 UTC ( #1047079=note: print w/ replies, xml ) Need Help??

in reply to Re^2: Wordfeud racks
in thread Wordfeud racks

Sorry, I meant permutations, so there a N!/(N-K)! ways to select K tiles from a bag of N.

Or for 7 of 100 tiles = 100*99*98*97*96*95*94 permutations.

I think it will be easier to calculate the probabilities of the different combinations rather than count them, but it's still going to be a fair amount of work.

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