concatenating text files before reading

[Hossein]

Hi,

I need to read several (small) text files (all files in same dir). The content of all files are supose to go into one scalar $content.

I think of concatenating them before I read them.

How should I do it in a smart and smooth way?

Thanks :)

/Hossein

[Eily]

The diamond operator has a bit of magic that could help. When used with an empty filehandle, it will read lines from all files in @ARGV. So you just have to put your input file list in @ARGV, and read it all with a while loop. And glob is your friend too.

local @ARGV = glob "folder/*.txt; # list of all .txt files in folder
print while (<>); # print each line of all those files

[Hossein]

Thank you :)

this was what I was looking for.

regards

Hossein

[Anonymous Monk]

Not really, too many caveats Write to existing file with character insert, Dangerous diamonds! safe diamonds FMTYEWTK About Mass Edits In Perl - Perl.com Good-bye Unix filter idiom

[hdb]

You could also do it on the command line:

cat *.txt | perl myscript.pl

[2teez]

Hi Hossein,
I need to read several (small) text files (all files in same dir)
look into using opendir to open your directory, then you can use readdir to get your files to read, using open.
However, one need ask; Is the ORDERing of your files contained in your directory important? If so, you might have to sort your file in a way to get the final content in the a correct order.
^* The content of all files are supose to go into one scalar $content
You can initialize a string say my $content = ""; then when you open and read through each of the files, chomping the newlines from each lines you can concatenate like so

...

while(my $line = <$fh>){
 chomp $line;  
 $content .= $line;
}

* Update.

[Hossein]

Thank you :) Sorting is not needed:)

Regards

Hossein

[Anonymous Monk]

How should I do it in a smart and smooth way?

Can you do it in such a way that you consider dumb/rough?

[Hossein]

I can write many lines of code to do it, but I'm sure there is a better and smarter way of doing it. That's why I asked for help:)

First thing I learned about Perl: "There are more than 1000 ways of doing it"

[Anonymous Monk]

I can write many lines of code to do it, but I'm sure there is a better and smarter way of doing it. That's why I asked for help:) First thing I learned about Perl: "There are more than 1000 ways of doing it"

If you remove the newlines then it all fits on one line -- I sure would like to see how you would do it

[Anonymous Monk]

my $textref = cat_files_ref( ... );
sub cat_files_ref {
  use File::Slurp;
  my $buffer = "";
  for my $file ( @_ ){
    read_file( $bin_file, buf_ref => \$buffer,
{ binmode => ':raw' } ) ;
  }
  return \$buffer;
}

sub cat_files_ref {
  use Path::Tiny;
  my $buffer = "";
  for my $file ( @_ ){
    $buffer .= path( $file )->realpath->slurp_raw;
  }
  return \$buffer;
}

sub cat_files_ref {
  use IO::All;
  my $content;
  for my $file ( @_ ){
    $content << io($file);
  }
  return \$content;
}