note
roboticus
<p>[phildeman]:</p>
<p>I like to invert the hash for things like this. This way, you get a list of the keys for each value:</p>
<c>
$ cat t.pl
#!/usr/bin/perl
my %hash = (key1=>10,key2=>10,key3=>3,key4=>5,key5=>10);
my %invhash;
while (my ($k,$v) = each %hash) {
push @{$invhash{$v}}, $k;
}
for my $v (sort {$a<=>$b} keys %invhash) {
print "$v cnt=", scalar(@{$invhash{$v}}),
" keys=",join(", ",@{$invhash{$v}}), "\n";
}
$ perl t.pl
3 cnt=1 keys=key3
5 cnt=1 keys=key4
10 cnt=3 keys=key5, key2, key1
</c>
<p>But if you don't find the list of keys useful, or if there's too much data, just incrementing a counter as you suggest will do the job.</p>
<p>...[roboticus]</p>
<p><i>When your only tool is a hammer, all problems look like your thumb.</i></p>
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