Re: Replacing a list with one variable


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Re: Replacing a list with one variable

by hdb (Monsignor)

on Nov 21, 2013 at 10:14 UTC ( [id://1063707]=note: print w/replies, xml )

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in reply to Replacing a list with one variable

It seems that the IDs parameter requires a reference to an array so you need to split your string $bookIDList into an array, the brackets will then turn that into a reference:

my $bookIDList = "abc,ghj,zxc,bnm,qwe,rty,iop,sdf,ert";
my $param = {
                 IDs => [ split /,/, $bookIDList ], 
                 sort => "AUTHOR",
                 maxResults => 100
              };
[download]

or you build a list in the first place and feed a reference to that list:

my @bookIDList = ( "abc", "ghj", "zxc", "bnm", "qwe", "rty", "iop", "s
+df", "ert" );
my $param = {
                 IDs => \@bookIDList, 
                 sort => "AUTHOR",
                 maxResults => 100
              };
[download]