Re: decoding pattern expression

[kennethk]

Is there any way I can do it with bash scripting ?

If you want bash scripting, you've come to the wrong site. If you'd like some help doing this with Perl scripting, I'd probably use indices 0-4 instead of A-E, make an array (my @values = (1, 7, 11, 3, 100)) and then split your coded strings:

my @terms = split //, $input;
my $sum = 0;
for my $i (0 .. @terms-1) {
    $sum += $values[$i] if $terms[$i] ne '?';
}
print "$input = $sum\n";

[AnomalousMonk]

Using substr might be slightly faster than split-ing to an array (YMMV):

c:\@Work\Perl>perl -wMstrict -le
"my @vectors = (
   [ '--+-+', 122 ], [ '---++', 122 ], [ '?????', 0 ],
   [ '-????',   1 ], [ '-???-', 101 ],
   );
 ;;
 my @map = (1, 7, 11, 3, 100);
 ;;
 use Test::More 'no_plan';
 ;;
 for my $ar_vector (@vectors) {
   my ($s, $expected) = @$ar_vector;
   ;;
   my $cvt = convert($s);
   ok $cvt == $expected, qq{'$s' -> $expected (got $cvt)};
   }
 ;;
 sub convert {
   my ($s) = @_;
   ;;
   my $sum = 0;
   $sum += substr($s, $_, 1) ne '?' ? $map[$_] : 0 for 0 .. length($s)
+-1;
   return $sum;
   }
"
ok 1 - '--+-+' -> 122 (got 122)
ok 2 - '---++' -> 122 (got 122)
ok 3 - '?????' -> 0 (got 0)
ok 4 - '-????' -> 1 (got 1)
ok 5 - '-???-' -> 101 (got 101)
1..5