Re: Template, sorting an array with only one member (code not words)

[Anonymous Monk]

Code talks louder than words :)

$ cat sort-list.tt2
[% MACRO blocker BLOCK %]
[% FOREACH element IN array.sort('name') %]
[% element.name %]
[%- END -%]
[%- END -%]

[%-
SET array = [
  { name => 'foo', value => 1 },
  { name => 'bar', value => 2 },
  { name => 'baz', value => 3 }
];
blocker
%]

[%-
SET array = [
  { name => 'bar', value => 2 },
];
blocker
%]

$ tpage sort-list.tt2


bar
baz
foo


bar

My code says it works ... so what does your code say?

[FloydATC]

I get the same result if I define the array within the template. If the array is served as a reference through Template::process() then it doesn't work as expected.

[Anonymous Monk]

I get the same result if I define the array within the template. If the array is served as a reference through Template::process() then it doesn't work as expected.

Thats just more words :) but I'm glad to see choroba got you to play ;) and you figured it out

[Anonymous Monk]

You must be giving it a hash instead of an array ... don't know how you managed to write that :)

[% MACRO blocker BLOCK %]
[%     FOREACH element IN array.sort('name') %]
[%         element.name %]
[%-    END -%]
[%- END -%]
[%-
SET array = [
      { name => 'foo', value => 1 },
      { name => 'bar', value => 2 },
      { name => 'baz', value => 3 }
    ];
    blocker;
%]
[%-
    SET array = [ { name => 'bar', value => 2 }, ];
    blocker;
%]
[%-
## A HASH IS NOT AN ARRAY OF HASHES
    SET array = { name => 'bar', value => 2 };
    blocker;
%]

yadayadayada

* bar
* baz
* foo

* bar

*
*