Re: And plus OR

[AnomalousMonk]

What does "does not work" mean?

c:\@Work\Perl\monks>perl -wMstrict -le
"my $username = 'phil';
 my $security = 'phil';
 my $type     = 'foo';
 ;;
 if (($username eq qq{$security}) && ($type ne 'Check In' || $type ne 
+'Check Out')) {
   print qq{\$username and \$security are '$username'};
   print qq{\$type is '$type'};
   }
"
$username and $security are 'phil'
$type is 'foo'

Update: Please see Short, Self Contained, Correct (Compilable), Example.

Update 2: After looking at tybalt89's guess about your difficulty, I think it's likely right: you're expecting the expression
    $type ne "Check In" || $type ne "Check Out"
to be false sometimes, and it can only be true.