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Re: Defereferncing an array gathered from an objectby KurtZ (Friar) |
on May 19, 2017 at 23:53 UTC ( [id://1190687]=note: print w/replies, xml ) | Need Help?? |
Please try
Hope this is what you really want. Update: If your intention is to join more than one $data array for the same $scopeName, you'd need:
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