Re: What regex can match arbitrary-length quoted string?

[AnomalousMonk]

Here's an example based on the pre-5.10  (?>pattern) atomic grouping. It should be fairly easily convertable to use the  + possessive quantifier modifier. (I'm using  'x' in place of  '"' because Windose command line and my REPL don't like double-quotes, but you get the idea.)

c:\@Work\Perl\monks>perl -wMstrict -le
"print 'perl version: ', $];
 print '------------';
 ;;
 my $non_x_or_escaped = qr{
   (?> [^x\\]{0,32766}) (?> (?> \\.){0,32766} (?> [^x\\]{0,32766}))
   }xms;
 ;;
 my $s = 'zx' . ('\x' x 1_000_000) . 'xz';
 print 'length of test string: ', length $s;
 print substr($s, 0, 20), ' ... ', substr($s, -20);
 ;;
 print 'MATCHED' if $s =~ m{ (x (?> $non_x_or_escaped)* x) }xms;
 my $captured = $1;
 print 'length captured: ', length $captured;
 print substr($captured, 0, 20), ' ... ', substr($captured, -20);
 print '------------';
 ;;
 $s = 'zx' . ('p' x 1_000_000) . '\x' . ('q' x 1_000_000) . 'xz';
 print 'length of test string: ', length $s;
 print substr($s, 0, 20), ' ... ', substr($s, -20);
 ;;
 print 'MATCHED' if $s =~ m{ (x (?> $non_x_or_escaped)* x) }xms;
 $captured = $1;
 print 'length captured: ', length $captured;
 print substr($captured, 0, 20), ' ... ', substr($captured, -20);
"
perl version: 5.008009
------------
length of test string: 2000004
zx\x\x\x\x\x\x\x\x\x ... \x\x\x\x\x\x\x\x\xxz
MATCHED
length captured: 2000002
x\x\x\x\x\x\x\x\x\x\ ... x\x\x\x\x\x\x\x\x\xx
------------
length of test string: 2000006
zxpppppppppppppppppp ... qqqqqqqqqqqqqqqqqqxz
MATCHED
length captured: 2000004
xppppppppppppppppppp ... qqqqqqqqqqqqqqqqqqqx