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Re: Collecting data in a recursive routine.

by chipmunk (Parson)
on Mar 07, 2002 at 04:38 UTC ( #149939=note: print w/replies, xml ) Need Help??

in reply to Collecting data in a recursive routine.

I see that you're fetching categories in groups, grabbing all the children of a specific category, then going on to the next parent category... My inclination would be to fetch all the categories at once, then organize them. Here's one way to do this:
my $cats_sth = $dbh->prepare(<<"EndOfSQL"); SELECT category_id, name, parent FROM $sql{categories} ORDER BY category_id ASC -- assumes parent id is always less than child id EndOfSQL my @cats; # build the data structure while (my($cat_id, $name, $parent_id) = $cats_sth->fetchrow_array()) { $cats[$cat_id] = [$name, $parent_id, []]; if ($cats[$parent_id]) { push @{$cats[$parent_id][2]}, $cat_id; } elsif ($parent_id) { warn "Parent $parent_id not found for category $cat_id '$name' +\n"; } } # print the categories foreach my $cat (@cats) { next unless $cat and !$cat->[1]; print_category($cat, \@cats, ''); } # recursively print a category and its children sub print_category { my($cat, $cats, $indent) = @_; print $indent, $cat->[0], "\n"; foreach my $child_id (@{$cat->[2]}) { print_category($cats->[$child_id], $cats, "$indent "); } }
The data structure that this uses is:
[ [ name, parent id, [ child ids ] ], [ name, parent id, [ child ids ] ], ... ]
where the ids are also the indexes into the array.

This probably is not the best data structure for your task, although it does get the job done. It should give you some ideas about solving the problem.

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[marto]: good afternoon all
[marto]: that is a neat feature, I'll have to have a look at how it displays that
[Tux]: 14:32 Europe/Amsterdam, so good afternoon to you :)
[marto]: 13:32, sunny Glasgow :P
[Tux]: as in, some others might appreciate a good morning or goor evening
[Tux]: Glasgow, as in TPCiG-2018 !!!! :) :)
erix would rather appreciate proof of a goodmorning
[marto]: Tux so I'm told :)

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