in any 1 roll, it rerolls the lowest number. It will also add the three highest sets of rolls and print it out. I know my version isn't as well done as others, but i didn't sit down to really work with it.. just fixed your code here and there to try and keep as much of it intact :).
#!/usr/bin/perl
use warnings;
use strict;
#Die Roller: uses 4d6 discarding the lowest number
#rerolling any roll of 1
my $roll = 6;
my @sums;
until ($roll == 0) {
my @d6;
chomp $roll;
$roll--;
$d6[0] = int(rand(6) + 1);
$d6[1] = int(rand(6) + 1);
$d6[2] = int(rand(6) + 1);
$d6[3] = int(rand(6) + 1);
@d6 = sort @d6;
$d6[0] = int(rand(6) + 1); #reroll lowest number
my $sum = $d6[0] + $d6[1] + $d6[2] + $d6[3];
push(@sums, $sum);
print "$d6[0], $d6[1], $d6[2], $d6[3] : $sum\n\n";
}
@sums = sort @sums;
my $three_highest = $sums[3] + $sums[4] + $sums[5]; #add three highest
+ numbers in array
print "total of three highest roles : $three_highest";
EDIT... posted too quick and didn't even read your post in whole (missed the reroll of ONLY 1's)... i guess you didn't want one that looked like your version either :P, nonetheless, i'll keep the code here for you :).
