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Answer: undef vs. $foo = 0

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Q&A > input and output > undef vs. $foo = 0 contributed by Mur

undef $bar may have some useful side-effects, if $bar is an object.
$bar = Foo->new(); ... undef $bar;
will invoke "Foo::DESTROY", if it is defined.
$bar = 0;
will also invoke DESTROY, but not if '0' is a valid assignment in the "Foo" class (long shot, I know).

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