Focus on the vowels. There are always fewer vowels than consonants, especially in junk, and all (English) words need at least one. So pick the next vowel, and see if you can make at least one word of it if you take a few letters in front and after it as well. Or: is this snippet of a few letters a substring of an existing word?
For many letters, that will be the case. For example, in your phrase, I can recognize "a", "real", "he", "her", "age". So don't throw away too many candidates upfront: none of these words here are the words of which the phrase actually consists. It's not because you found a word that it is the word. Note that you can hardly find any words at all in the junk string. So this one is quickly dismissed.
Well, eventually, you'll have them all fit the whole string, so you have only words and no excess letters between them. (Er, what do you do with spelling errors?). So if you do find a likely substring around a vowel, concentrate on the next vowel that isn't part of this word. You should find two words that fit both sequences with no letters between them. If you don't, and not for any group around each vowel, the string must be junk.