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Perl 6's part()

by BrentDax (Hermit)
on Jan 10, 2003 at 03:21 UTC ( #225721=snippet: print w/replies, xml ) Need Help??
Description: Perl 6 is slated to include a new list manipulation function, part (for partition, although Damian likes it 'cause it can mean so many other things). It takes a codeblock and a list; the codeblock returns an index, and part puts it into an arrayref corresponding to that index. For example:
my($good, $bad, $ugly)=part { /good/ ? 0 : /bad/ ? 1 : /ugly/ ? 2 : (warn "$_ didn't categorize" and 3) } @people;
If you replace the $good, $bad, and $ugly with *good, *bad, and *ugly in that example, you'll get the arrays in @good, @bad and @ugly.
sub part(&@) {
    my($code, @list)=@_;
    my @ret=();
    push @{$ret[&$code()]}, $_ for @list;
    return @ret;
}
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Re: Perl 6's part()
by jdporter (Canon) on Jan 10, 2003 at 03:52 UTC
    Hmm. Interesting.
    I like that I can do this:
    my %h; @h{qw( good bad ugly )} = part { /good/ ? 0 . . . } @people;

    jdporter
    The 6th Rule of Perl Club is -- There is no Rule #6.

Re: Perl 6's part()
by mojotoad (Monsignor) on Jan 10, 2003 at 17:58 UTC
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