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Of course &lc doesn't work

by chip (Curate)
on Jul 28, 2000 at 15:20 UTC ( #24827=note: print w/ replies, xml ) Need Help??


in reply to Subtle Quirks

After all, &lc is how you tell Perl that you want to call a function named "lc", as opposed to the default behavior attached to that name ... namely, the lc operator.

    -- Chip Salzenberg, Free-Floating Agent of Chaos


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RE: Of course &lc doesn't work
by beppu (Friar) on Jul 28, 2000 at 16:07 UTC
    I didn't try &lc. I tried \&lc. (Is the backslash showing up?) I tried to take the reference of lc, because I thought (mistakenly) that built-ins and subroutines could be treated the same way.
      Yes, the backslash came through. But taking a ref to a sub only works if there's a sub there to take a ref to. The idea of \&lc reminds me of that famous description of Oakland: ``There's no `there' there.''

          -- Chip Salzenberg, Free-Floating Agent of Chaos

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