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Can I break out of a subroutine before the end?

by Anonymous Monk
on Aug 30, 2000 at 12:24 UTC ( #30266=perlquestion: print w/replies, xml ) Need Help??
Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

You can break out of a subroutine by using the return keyword :

#!/usr/bin/perl -w use strict; sub test { my ($param) = @_; if ($param =~ /e/) { print "e found.\n"; return; }; print "No e found.\n"; }; &test( "test" ); &test( "toast" );
Note that jumping out of the middle of a subroutine is considered bad style by some people who do believe in the statement that every routine should have one entrypoint and one exit.

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Re: Can I break out of a subroutine before the end?
by AcidHawk (Vicar) on Apr 30, 2003 at 08:20 UTC

    To simplify the given example and keep to the "one entry point one exit point to and from a subroutine" style, I would only add an else to the subroutines if statement Check the following:

    #!/usr/bin/perl -w use strict; sub test { my ($param) = @_; if ($param =~ /e/) { print "e found.\n"; } else { print "No e found.\n"; } }; &test( "test" ); &test( "toast" );
    I have also tried the following in case there are more than two options ie (more than true or false). I have only one entry point in a subroutine and one exit from that routine. It does mean though that I have to test the return value of the subroutine. Using the same example as above I could expand the tests (if statements) and the value that is returned, and then test these values later. E.g.
    #!/usr/bin/perl -w use strict; sub test { my ($param) = @_; my $rc = 0; if ($param =~ /e/) { $rc = 1; } elsif ($param =~ /a/) { $rc = 2; } return($rc); }; my @tsts = qw/ test toast kitty /; foreach my $word (@tsts) { my $ret_val = &test($word); if ($ret_val == 1) { print "E found\n"; } elsif ($ret_val == 2) { print "A found\n"; } else { print "A or E NOT found\n"; } }

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