This is just a hunch, but could it be that the $i in the last example is treated as a reference at the end, so that the sub is not evaluated until in the last block. So it is evaluated to the last value of $i, the value that triggered the exit from the construction loop.

Maybe this should be fixed with scoping $i so it can't be reached by the last block?

update:This is a bit silly, but this is the way I solved it when I had the same problem ("my $o" in second last block):

my ( @ref_list, $code_ref, $i );

#pass one
#for SCALAR LIST
for $i (1..8) {
    push( @ref_list, sub { print "    \$i == $i\n" } );
}

print "for SCALAR LIST\n";
while ( $code_ref = pop @ref_list ) {
    &$code_ref;
}

#pass 2
#for INIT ; TEST ; INCREMENT
for (  $i = 1; $i <= 8; $i++ ) { 
    my $o;
    $o=$i;
    push( @ref_list, sub { print "    \$i == $o\n" } );
}

print "for (;;)\n";
while ( $code_ref = pop @ref_list ) {
    &$code_ref;
}
[download]

/jeorgen

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