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I did some studying on non-determinism.

An example of a non-deterministic algorithm is mergesort.

use sort '_mergesort'; my @sorted = sort { substr($a, 0, 1) cmp substr($b, 0, 1) } qw( foo bar baz );

It is guarantees that the results will the sorted, but the relative ordering of baz and bar is not specified. Therefore, mergesort is non-deterministic.


Let's see if we can replicate the same situation with the parser.

The goals of Perl's parser include the production of functions.

package Mod; BEGIN { my ($sub) = map "sub { $_ }", join ' ', map "$_();", sort { substr($a, 0, 1) cmp substr($b, 0, 1) } qw( foo bar baz ); } sub foo { print "$foo\n" }; sub bar { print "$bar\n" }; sub baz { print "$baz\n" }; 1;

The parser produces a function that calls foo(), bar() and baz(), but the order in which the calls are organized is not specified. Therefore, the parser is non-deterministic.


I don't know what that means wrt Perl's parsability, since I don't know I don't know how that's defined.


In reply to Re^4: Unparseability is A Good Thing by ikegami
in thread Unparseability is A Good Thing by Jeffrey Kegler

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