I am trying to use a perl one liner as

my $stat = $ssh->exec("perl -e /.firstboot | echo $?");
[download]

and what i want is to have $stat = 0 , if the file does not exist, and 1 f it does but i am getting an error: Search pattern not terminated at -e line 1. Need some help please Thanks, -Kamal. here is the whole script:

#!/usr/bin/perl
use Net::SSH::Expect;
use YAML;
use Data::Dumper;
use warnings;
use strict;
use diagnostics;

#####################
# process the input
#####################
my $in = YAML::LoadFile('test_input.yml');

my $version   = $in->{test_instance}{version};
my $build     = $in->{test_instance}{build};
my $host_data = $in->{host}[0];
my $modelnum  = $host_data->{model_number};
my $company   = $host_data->{company};
my $address   = $host_data->{address};

#print Dumper($address), "\n";

my $ssh = Net::SSH::Expect->new(
    ssh_option => "-v -v -v",
    #ssh_option => "-v",
    #host       => $address,
    host => "baseline-dc1",
    #host => "upgrade-dc1",
    #host => "upgrade-3d1",
    #host  => "baseline-3d1",
    #host => "batterup-dc2",
    user     => 'admin',
    #password => 'password',
    raw_pty  => 1,
    #timeout => 2,
    log_stdout     => 1,
        ssh_option => '-o StrictHostKeyChecking=no '
      . '-o UserKnownHostsFile=/dev/null '
      . '-o LogLevel=ERROR'
);
$ssh->run_ssh();
$ssh->exec("stty raw -echo");
#my $ls = $ssh->exec("ls -l /");
  #      print($ls);
        
    #    my $who = $ssh->exec("who");
    #    print ($who);
        $ssh->send("sudo -i");
        $ssh->waitfor('Password:', 3);
        $ssh->send("Sourcefire");


print "logged in?\n";

    my $catschedular = $ssh->exec("cat /sys/block/sda/queue/scheduler"
+);
    my $echoconf = $ssh->exec("echo '/usr/lib/bigloo/3.1a' >> /etc/ld.
+so.conf");
    my $catconf = $ssh->exec("cat /etc/ld.so.conf");
    my $ldconfig = $ssh->exec("ldconfig");

print "the part we care about:\n\n\n";

my $stat = $ssh->exec("if [ -e /.firstboot ]; then echo 1; else echo 0
+; fi");
#my $stat = $ssh->exec("[ -f /.firstboot ] && echo "1" || echo "0"");
open OUT, "> /tmp/STAT.out";
print OUT $stat;
close OUT;

print "stat:|".$stat."|";
chomp $stat;
my $newstat;
$newstat = substr($stat, 0, 1);
$stat = $newstat;

print "new stat: |" . $newstat . "|\n";
print "old stat: |" . $stat . "|\n";

 # testport returns 0 if the port accepts tcp connections
    my $https=system("testport $address 443");

        print "before..."."|".$https."|";
        chomp $https;
        print "after..."."|".$https."|";
[download]

The problem, is that /tmp/STAT.out contains the "prompt" in addition to "0" and i just want "0" which is the value of $stat

---

---

• Are you posting in the right place? Check out Where do I post X? to know for sure.
• Posts may use any of the Perl Monks Approved HTML tags. Currently these include the following:

  <code> <a> <b> <big> <blockquote> <br /> <dd> <dl> <dt> <em> <font> <h1> <h2> <h3> <h4> <h5> <h6> <hr /> <i> <li> <nbsp> <ol> <p> <small> <strike> <strong> <sub> <sup> <table> <td> <th> <tr> <tt> <u> <ul>

• Snippets of code should be wrapped in <code> tags not <pre> tags. In fact, <pre> tags should generally be avoided. If they must be used, extreme care should be taken to ensure that their contents do not have long lines (<70 chars), in order to prevent horizontal scrolling (and possible janitor intervention).
• Want more info? How to link or How to display code and escape characters are good places to start.