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how do I use a hash of hashes reference in a function ?

by Anonymous Monk
on Sep 22, 2000 at 21:44 UTC ( [id://33662]=perlquestion: print w/replies, xml ) Need Help??

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

This is a rephrased version of my previous question.
I can pass a hash of hashes to a function OK:
$hash{name} = {date => "00-22-00", city=>"Chicago",}; function (\%hash1); function (\%hash2);

However I've tried several examples given previously and none work completely
sub function { my %hashref=%{shift()}; #the below works ok print $hashref{name}{city},"\n"; # but adding to the hash doesn't work if I print out # the entire hash outside this function $hashref{name}={data1=>"moredata",}; # it does work if I print it out inside the function }

Replies are listed 'Best First'.
Re: how do I use a hash of hashes reference in a function ?
by merlyn (Sage) on Sep 22, 2000 at 21:53 UTC
    $hashref{name}={data1=>"moredata",};
    Wrong syntax for adding to a hash. Use this:
    $hashref{name}{data1} = "moredata";
      Just for clarification (for the original poster), your syntax:
      $hashref{name} = { data1 => "moredata" };
      *replaces* the reference in $hashref{name} with a new one, composed of your data1 => "moredata" hash. That's why it won't work. merlyn is correct in that if you wish to modify the hash referenced by $hashref{name} you don't do that by setting $hashref{name}, you modify it as if it were a hash: $hashref{key}{subkey} = $xyz;

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