Re^2: What's the difference between stat and sort?

[PetaMem]

Aaah. As the germans say: "I get the crisis!"

my $lf = (sort(<*>))[-1];
print $lf,"\n";

works. While the (what I tested)

print (sort(<*>))[-1], "\n";

throws a

print (...) interpreted as function at ./template.pl line 6.
syntax error at ./template.pl line 6, near ")["
Execution of ./template.pl aborted due to compilation errors.

[Chady]

print (...) interpreted as function...

possible solutions:

print ((sort(<*>))[-1]), "\n";
# or
print+(sort(<*>))[-1], "\n";

see also print (...) interpreted as function

[beable]

Oh that's easy, parenthesisation. Try this:

perl -e 'print((sort(<*>))[1]);'

Once the expression is fully inside parentheses, there is no syntax error. With the square brackets outside the parens, it must be trying to get the first element of the array returned by print(), which doesn't return an array.