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Re^2: Perlish way of doing thisby htoug (Deacon) |
on Dec 08, 2004 at 12:53 UTC ( [id://413185]=note: print w/replies, xml ) | Need Help?? |
Ahhh, now I see. Ie after you updated the question. I think that it could be simplified by noting that the two tmp-arrays can be created given only one of the input arrays - @tmp1 depends only on @a1 and @tmp2 only on @a2. Your loop could be shortened to something like: That satisfies your explanation. But your code seems to indicate that the value is put into the tmp-arrays also if the value is present in neither the @a1 or @a2. Unfortunately your code does not have an example of this, so it cannot be tested.
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