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Re^2: Perlish way of doing this

by htoug (Deacon)
on Dec 08, 2004 at 12:53 UTC ( #413185=note: print w/ replies, xml ) Need Help??


in reply to Re: Perlish way of doing this
in thread Perlish way of doing this

Ahhh, now I see. Ie after you updated the question.

I think that it could be simplified by noting that the two tmp-arrays can be created given only one of the input arrays - @tmp1 depends only on @a1 and @tmp2 only on @a2.

Your loop could be shortened to something like:

for my $elem (sort keys %a) { push @tmp1, (grep($elem eq $_} @a1) ? $elem : "##"; push @tmp2, (grep($elem eq $_} @a2) ? $elem : "##"; }
That satisfies your explanation.

But your code seems to indicate that the value is put into the tmp-arrays also if the value is present in neither the @a1 or @a2. Unfortunately your code does not have an example of this, so it cannot be tested.


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