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### Re^2: getting the highest value in a simpler way

by uksza (Abbot)
 on Dec 19, 2004 at 02:31 UTC ( #415930=note: print w/replies, xml ) Need Help??

Hello!

```\$highestvalue = [ \$x => \$y ] -> [ \$x <= \$y ]
Anybody can explanin me this code? I'm a bit confused ;-)

Uksza

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Re^3: getting the highest value in a simpler way
by BrowserUk (Pope) on Dec 19, 2004 at 03:07 UTC

[ \$x => \$y ] is the same as [ \$x, \$y ] which is the essentially the same as

```my \$ary = ( \$x, \$y );
my \$aryRef =  \ @ary;

And \$x <= \$y is just a boolean expression that will give a false (0) result if \$x > \$y and true value (1) otherwise.

\$aryRef->[ 0/1 ] will return either \$ary[ 0 ] or \$ary[ 1 ].

Putting it all together, you get an expression that will construct an anonymous array containing \$x, \$y, then dereferences that anonmous array and uses the boolean result of the comparison to select the greater of the two values before assigning it to the scalar.

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Hey!

I understand!! ;-)
So, in exmaple:
```my \$x = 5
my \$y = 10
my \$highestvalue = [ \$x => \$y ] -> [ \$x <= \$y ]

#we have @aray(5,10) and because (5 <= 10) it returns 1, so

\$highestvalue = aray[1]

thats mean 10 in this example, right?

Eh, nice trick... ;-)
Uksza

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