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Re: Math::BigInt Newbee question.

by Paladin (Priest)
on Jan 27, 2005 at 16:57 UTC ( #425624=note: print w/replies, xml ) Need Help??

in reply to Math::BigInt Newbee question.

When I run that code, I get
$ perl 2 675 Global symbol "$arg2" requires explicit package name at line 2 +0. Execution of aborted due to compilation errors.

So I am guessing that the code you pasted is not the code that's actually running. You don't declare $arg2 and are missing ->new in a few places.

Also, bdiv and bmul modify inplace. I believe what you were trying to write is:

#!/usr/bin/perl -w use strict; use Math::BigInt; #BigInt KiloByte Unit my $KB = Math::BigInt->new( "1024" ); #BigInt MegaByte Unit my $MB = $KB->copy()->bmul( $KB ); #BigInt GigaByte Unit my $GB = $MB->copy()->bmul( $KB ); print "$KB, $MB, $GB\n"; my $arg1 = Math::BigInt->new( shift ); my $arg2 = Math::BigInt->new( shift ); # arg1 is in GBs my $GBarg1 = $arg1->copy()->bmul( $GB ); # arg2 is in MBs my $MBarg2 = $arg2->copy()->bmul( $MB ); print $GBarg1, " ", $MBarg2, "\n"; # why rc is 0? my ($rc, $rem) = $GBarg1->copy()->bdiv( $MBarg2 ); print "rc is [$rc]\n";
Note: Also, to be really correct, you will need to add 1 more CD to the final result to take up the remainder of the data.

Update: Clean up code a bit

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Re^2: Math::BigInt Newbee question.
by ikegami (Pope) on Jan 27, 2005 at 17:20 UTC

    I think you can also do my $MB = $KB * $KB; instead of my $MB = $KB->copy()->bmul( $KB ); thanks to overloaded operators.

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