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Re^2: What is the point of the & sigil for function refs?

by ihb (Deacon)
on Feb 11, 2005 at 14:20 UTC ( #430108=note: print w/replies, xml ) Need Help??

in reply to Re: What is the point of the & sigil for function refs?
in thread What is the point of the & / ampersand sigil for function refs?

the local @_ is implicitly passed

It's even the same @_. This means that &foo(@_) and &foo; won't behave the same; see perlfaq7, "What's the difference between calling a function as &foo and foo()?". Demonstration:

use strict; sub foo { pop } sub bar { print "bar before: @_"; print '&foo : ' . &foo . " <--- I am a theif"; print "bar after : @_ <--- no c"; } sub baz { print "baz before: @_"; print '&foo(@_) : ' . &foo(@_); print "baz after : @_"; } bar(qw/ a b c /); print ''; baz(qw/ a b c /); __END__ bar before: a b c &foo : c <--- I am a theif bar after : a b <--- no c baz before: a b c &foo(@_) : c baz after : a b c


See perltoc if you don't know which perldoc to read!

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