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Re^2: Golf: Buying with exact change

by dragonchild (Archbishop)
on Feb 22, 2005 at 14:44 UTC ( #433346=note: print w/replies, xml ) Need Help??

in reply to Re: Golf: Buying with exact change
in thread Golf: Buying with exact change

Golfed, I get you down to 140, assuming the inputs are ordered smallest to largest. Interestingly enough, if you have the defined-or patch, I get down to 122. If the inputs aren't ordered, add 13 characters to both solutions.
Without //= patch: @x=@_;my%c;$e=sub{my$v=pop;exists$c{$v}?$c{$v}:$c{$v}=$v<0?0:$v==0||gr +ep&$e($v-$_),@x};$t=$s=0;{&$e(++$t)?$t-$s>=$x[0]&&last:($s=$t);redo}$ +s With //= patch: @x=@_;my%c;$e=sub{my$v=pop;$c{$v}//=$v<0?0:$v==0||grep&$e($v-$_),@x};$ +t=$s=0;{&$e(++$t)?$t-$s>=$x[0]&&last:($s=$t);redo}$s

Update: Actually, the inputs don't have to be ordered. It just means that the algorithm will take a little longer, but it will get the right results. Also, drop a character by reordering the assignment to $c{$v}. The //= patched version looks like:
@x=@_;my%c;$e=sub{my$v=pop;$c{$v}//=$v==0||$v>0&&grep&$e($v-$_),@x};$t +=$s=0;{&$e(++$t)?$t-$s>=$x[0]&&last:($s=$t);redo}$s

Update: Rewriting the redo-loop as a C-style for-loop drops to 111 characters for the //= patched version.
@x=@_;my%c;$e=sub{my$v=pop;$c{$v}//=!$v||$v>0&&grep&$e($v-$_),@x};for( +$t=$s=0;$t-$s<$x[0];&$e(++$t)or$s=$t){}$s

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