in reply to
Re^2: Challenge: Another Infinite Lazy List
in thread Challenge: Another Infinite Lazy List
It looks like we're working with the same data, though I don't think we're doing the same thing with it to get our results. Here's mine explained: Each stream stores its base (2, 3, or 5) and the multiplier last used with that base to generate an output element. To generate the next element of the sequence, I check what the next output would be from each stream (multiply the base by the last multiplier + 1) and choose the lowest of those, incrementing the multiplier of each stream that would give me that lowest number. That's it.
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