Re: Sort - can't

[malaga]

sorry - i was abbreviating. the only place i'm having a problem is in the sorting. so, let me start over:

array looks like this:
category_Title Words_1 
category_Title Words_2 
category_Title Words_3 
category_Title Words_4 

($sub1, $sub2, $sub3) = split (/\_/, @array,3);
$sub3 = sort { $b <=> $a } $sub3;

doesn't work. i've also tried: 
my @newarray = ($sub1,$sub2,$sub3);
@newarray = sort { $a->[2] cmp $b->[2] } @newarray;

[QM]

You've failed again to ask your question appropriately.

First the diagnoses:

($sub1, $sub2, $sub3) = split (/\_/, @array,3);

split doesn't work on an array!!!

while my $elem (@array)
{
  ($sub1,$sub2,$sub3) = split(/_/, $elem, 3);
  # do something here...
}

Now you might have something in $sub3, but this doesn't make any sense either:

$sub3 = sort { $b <=> $a } $sub3;

You can't sort a scalar (well, it doesn't do anything interesting)

Seems what you really want to do is sort the elements of @array by the last field (numerically), in which case you'll need something like this:

my @a2;
while my $elem (@array)
{
  my @fields = split(/_/, $elem, 3);
  push @a2, \@fields;
}
my @a3 = sort { $b->[2] <=> $a->[2]} @a2;

But you should really see How (Not) to Ask a Question.

[fishbot_v2]

I think that you are actually having trouble with spliting, not so much with the sorting. split acts on a scalar at a time. I'm guessing that you want something more like this:

my @split_arr = map { [ split /_/, $_, 3 ] } @array;
my @sorted = sort { $a->[2] <=> $b->[2] } @split_arr;

Or more verbosely:

my @split_arr;
for ( @array )
{
   my @split_elem = split /_/, $_, 3;
   push @split_arr, \@split_elem;
}
my @sorted = sort { $a->[2] <=> $b->[2] } @split_arr;

Update: changed my guess at what you want from string sort to numeric sort.

[sk]

assuming you want to sort by category/title/number

#!/usr/bin/perl -w

use strict;

my @array = qw (biology_humananatomy_2 math_riemannhypothesis_1 biolog
+y_humananatomy_1 );
my @AoA;

for (@array) {
    push(@AoA,[split /\_/,$_,3]);
}

my @final = sort {$a->[0] cmp $b->[0] ||
                  $a->[1] cmp $b->[1] ||
                  $a->[2] <=> $b->[2]} @AoA;

for (@final) {
    print join('_',@$_),$/;
}

output:

biology_humananatomy_1
biology_humananatomy_2
math_riemannhypothesis_1

Please read other posts to understand why your code does not work.

cheers

SK

[chas]

"($sub1, $sub2, $sub3) = split (/\_/, @array,3);
$sub3 = sort { $b <=> $a } $sub3;"


It isn't clear to me what your array is exactly, but in any case, as has been remarked already, $sub3 will be a single string, and sorting it will have no effect. It isn't clear to me what you want to do or I would have offered more suggestions.
chas
(Update: Actually, what I said is misleading. I *think* the first line of the code above will take @array in scalar context giving the number of elements, and then $sub1 will be this value; $sub2 and $sub3 will be empty. The sorting will do nothing useful, of course. So perhaps you should just ignore my reply above and read the other replies...)

[tlm]

Sort what by what?

Your code is too way off for me to decipher your intentions.

If you want to sort the filenames by the substring after the last _, then I'd do something like

my @sorted =
  map $_->[ 0 ],
  sort { $a->[ 1 ] cmp $b->[ 1 ] }
  map [ $_, ( split '_' )[ -1 ] ],
  @unsorted;

(untested).

[malaga]

thanks everybody. i get it now and fixed it. I did know I was doing it all wrong of course, that's why i posted. For some reason I couldn't see where the scalars and arrays were in this. everything was working till i had to add the sort - i wasn't able to back out and see where changes had to be made. i appreciate the help. hopefully people learn from my dumb posts.

#SEARCH THROUGH THE CONTENT DIRECTORY AND FIND THE FILES THAT MATCH
chdir("$contentdir");#change to the content directory
my $stuff = ".";#make it $_
opendir THISDIR, "$stuff";#open the content directory
my @submenu = readdir THISDIR;#put the names of the files in an array
closedir THISDIR;
for (1..2) {shift @submenu;} 

my @aaa;
for (@submenu) {
push(@aaa,[split /\_/,$_,3]);
}

my @final = sort {$a->[2] <=> $b->[2] } @aaa;
for (@final) {
my $cat=$_->[0];
my $title=$_->[1];
my $rankk=$_->[2];
(my $rank, $tossit) = split (/\./, $rankk,2);

#foreach submenu item print it
if ($cat=~$main)
{
$counter++;
if ($counter > 1) {
print "<a href \= \"/cgi-bin/idx.pl?$sub1$sep$sub2$sep$sub3\">";
print "$sub2";
print "</a>";

etc., etc. i know this isn't pretty, but it is what it is.

[QM]

For some reason I couldn't see where the scalars and arrays were in this.

Here's a tool you already have to help you with this: Perl debugger!

Use the x command to see what a variable holds. It shows you the complete structure as if it were an array at the top level. (So hashes show up better if you escape the percent sign, as in the first example below).

c:\perl\perl>perl -de 0

Loading DB routines from perl5db.pl version 1.28
Editor support available.

Enter h or `h h' for help, or `perldoc perldebug' for more help.

main::(-e:1):   0
  DB<1> %x = ( 123, [ qw(one two three) ], 456, [ qw(four five six) ],
+ 789, [ qw(seven eight nine) ] )

  DB<2> x \%x
0  HASH(0x1d6c490)
   123 => ARRAY(0x15d52a4)
      0  'one'
      1  'two'
      2  'three'
   456 => ARRAY(0x1d6c628)
      0  'four'
      1  'five'
      2  'six'
   789 => ARRAY(0x1d6c664)
      0  'seven'
      1  'eight'
      2  'nine'
  DB<3> @x = ( { 1, "one", 2, "two", 3, "three" }, { 4, "four", 5, "fi
+ve", 6, "six" }, { 7, "seven", 8, "eight", 9, "nine" } )

  DB<4> x @x
0  HASH(0x1d70b24)
   1 => 'one'
   2 => 'two'
   3 => 'three'
1  HASH(0x1d97a78)
   4 => 'four'
   5 => 'five'
   6 => 'six'
2  HASH(0x1d97ab4)
   7 => 'seven'
   8 => 'eight'
   9 => 'nine'
  DB<5>