Re^2: Shortcut operator for $a->{'b'}=$b if $b;

[chester]

What's the for doing, there? Doesn't this work?

$b and $a->{'b'} = $b

edit: Doesn't solve the problem fully.

[merlyn]

I thought the point was that $b was standing in for something very complex or impossible to repeat for calculation.

[chester]

Ah, I see. My mistake.

[ikegami]

foreach loops sets $_ to refer to the current value in the list which is being iterated. In this case, the list consists solely of $b.

Your expression is equivalent, but it's not an acceptable answer since the question was about removing the need for using $b twice.