Beefy Boxes and Bandwidth Generously Provided by pair Networks
Don't ask to ask, just ask

Re^2: Obtaining terms in an expansion

by runrig (Abbot)
on Jan 05, 2006 at 23:40 UTC ( #521389=note: print w/ replies, xml ) Need Help??

in reply to Re: Obtaining terms in an expansion
in thread Obtaining terms in an expansion

You have N terms going in, and N terms coming out. He says in the OP that he wants 2^N expressions returned. This is considered 2 terms, so there are 4 expressions returned.

Update: my mistake. Did not read carefully enough.

Comment on Re^2: Obtaining terms in an expansion
Re^3: Obtaining terms in an expansion
by trammell (Priest) on Jan 06, 2006 at 15:16 UTC
    That's funny, because when I run the program for N=2, I get:
    term[0] = a[0][0] a[1][0] a[2][0] term[1] = a[0][0] a[1][0] a[2][1] term[2] = a[0][0] a[1][1] a[2][0] term[3] = a[0][0] a[1][1] a[2][1] term[4] = a[0][1] a[1][0] a[2][0] term[5] = a[0][1] a[1][0] a[2][1] term[6] = a[0][1] a[1][1] a[2][0] term[7] = a[0][1] a[1][1] a[2][1]
    So perhaps I have an off-by-one error, but certainly I'm generating 2^N terms.

Log In?

What's my password?
Create A New User
Node Status?
node history
Node Type: note [id://521389]
and the web crawler heard nothing...

How do I use this? | Other CB clients
Other Users?
Others meditating upon the Monastery: (7)
As of 2015-01-28 07:51 GMT
Find Nodes?
    Voting Booth?

    My top resolution in 2015 is:

    Results (213 votes), past polls