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Re^2: the basic datatypes, three

by sanPerl (Friar)
on Jan 24, 2006 at 11:22 UTC ( #525156=note: print w/ replies, xml ) Need Help??


in reply to Re: the basic datatypes, three
in thread the basic datatypes, three

Why do we need to key scalar(@list) when only @list would also work?
for e.g.

use strict; my @abc= ('a','b','c','d'); my $x= @abc; my $y = scalar(@abc); print $x."#".$y;
Here $x & $y both return 4.


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Re^3: the basic datatypes, three
by merlyn (Sage) on Jan 24, 2006 at 14:10 UTC
    The "scalar" op is needed only to provide scalar context in an otherwise list context space. For example:
    my @lengths = scalar @x, scalar @y, scalar @z; # but... my $length_x = @x; my $length_y = @y; my $length_z = @z;
    The scalar is needed in the first example because the array names are in a list context otherwise.

    -- Randal L. Schwartz, Perl hacker
    Be sure to read my standard disclaimer if this is a reply.

Re^3: the basic datatypes, three
by perladdict (Chaplain) on May 09, 2006 at 13:12 UTC
    In this example ,assigning a list to a scalar variable returns the result as a total number of elements in a list
      assigning a list to a scalar variable returns the result as a total number of elements in a list

      No. That's not right. Evaluating a list in a scalar context (by, for example, assigning it to a scalar) returns the last item in the list. Evaluating an array in scalar context returns the number of items in the array.

      There is an important difference between a list and an array.

      # Assign a list to a scalar my $scalar = ('A', 'B', 'C'); print "$scalar\n"; # $scalar is C # Assign an array to a scalar my @array = ('A', 'B', 'C'); $scalar = @array; print "$scalar\n"; # $scalar is 3
      Update: Stupid typo fixed.
      --
      <http://dave.org.uk>

      "The first rule of Perl club is you do not talk about Perl club."
      -- Chip Salzenberg

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