substitution of a string with Square brackets.

[neeha]

Hi Experts,
The below code does some substitution

$line =~ s#$methodname\(($2)\)#private $methodname($2)#g

Here $2 is the values in the parameters.
If the value of $2 is "String str". It works fine
But if value of $2 is "String str[]".
Unmatched [ in regex; exception occurs.
THis happens only with Square brackets
How can i do the substitution of a string with Square brackets.
Waiting for ur replies.
Thanks,
Swarna.

[GrandFather]

Use \Q and \E to quote the string:

$line =~ s#$methodname\((\Q$2\E)\)#private $methodname($2)#g

[salva]

use quotemeta to escape any special char in $2:

my $args = quotemeta $2;
$line =~ s#$methodname\(($args)\)#private $methodname($1)#g;

[Samy_rio]

Hi, Try like this,

Untested

$line =~ s#$methodname\((\Q$2\E)\)#private $methodname($2)#g

[Melly]

s#$methodname\((\Q$2\E)\)#private $methodname($2)#g

should fix it... although I am somewhat suspicious as to what you are doing with $2...

[mickeyn]

you should wrap $2 with quotes, i.e. \Q$2\E

$line =~ s#$methodname\((\Q$2\E)\)#private $methodname(\Q$2\E)#g

Enjoy,
Mickey