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Re^2: qx and $!

by blazar (Canon)
on Oct 18, 2006 at 16:19 UTC ( #579127=note: print w/replies, xml ) Need Help??


in reply to Re: qx and $!
in thread qx and $!

Update: Hey, no fair davorg! You clearly have the perldocs memorized, whereas I had to go look it up; that's why you beat my answer! :)

It's not fair only if you assume that there's a competition going on, at who answers the first - although I admit I like to be the one myself, on occasions. Otherwise, repetita iuvant. (Latin idiomatic expression which means "repetitions help".) Well, if taken in non excessive doses, cum grano salis...

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