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Re: Conditional Operator Confusion

by Herkum (Parson)
on Nov 29, 2006 at 13:17 UTC ( #586687=note: print w/ replies, xml ) Need Help??


in reply to Conditional Operator Confusion

Try this instead,

for (1..10) { $x = $_ > 5 ? 'foo' : 'bar'; print "$_:$x\n"; }

Ah, I just noticed that you had tried that in your second example. The real issue that you had was that you were trying to treat a trinary operator like an if-else statement. I have tried that before and it just don't work! :)


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Re^2: Conditional Operator Confusion
by Melly (Hermit) on Nov 29, 2006 at 15:48 UTC

    Hey! The camel book told me it was just like an if-else (well, sort of). Hmm, I must admit that I'm still slightly in the dark here - none of the examples given so far help me understand exactly what is going on...

    map{$a=1-$_/10;map{$d=$a;$e=$b=$_/20-2;map{($d,$e)=(2*$d*$e+$a,$e** 2-$d**2+$b);$c=$d**2+$e**2>4?_:0}1..99;print$c}0..59;print$/}0..20;
    Tom Melly, pm@tomandlu.co.uk

      The trinary is much like any other operator, for example ==. Lets try this example,

      my $result = $a == $b

      Here, you get the result of the == operator, is $a equal $b. If they match it returns true, if they don't match it returns false.

      The trinary works in a similar manner except you are setting the value returned instead of the implied value of other operators.

      my $result = $a == $b ? 1 : 0;

      This does the same thing as the first example, except you are explicitly setting the value returned. Does this help?

        Not really... I'm sure I'm being really dumb here, but I still don't understand, in the following example, why $x gets set to "FALSE"... just very, very confused...

        1==1?$x='TRUE':$y='FALSE'; print "x=$x\n";
        Tom Melly, pm@tomandlu.co.uk

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