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Re^4: removing the goto

by imp (Priest)
on Jun 01, 2007 at 19:26 UTC ( #618828=note: print w/replies, xml ) Need Help??


in reply to Re^3: removing the goto
in thread removing the goto

The point of redo is that it does not advance the iterator.
The redo command restarts the loop block without evaluating the conditional again.
my $redid = 0; my @list = (1..5); xyz : for (@list) { print; redo if $_ == 3 && ! $redid++; } # Output: 123345

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Re^5: removing the goto
by shmem (Chancellor) on Jun 01, 2007 at 20:09 UTC
    Thanks... now I got it *blush* - the difference between redo and next.
    Shame on me.

    --shmem

    _($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                                  /\_¯/(q    /
    ----------------------------  \__(m.====·.(_("always off the crowd"))."·
    ");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

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[shmem]: Discipulus: the <<>> operator is quite new, it is in perl5.24 for instance
[Discipulus]: ah! thanks shmem it works in strawberry 5.24
[shmem]: ah. Introduced in 5.22.0, see perl5220delta
[Discipulus]: if so the previous error is a bit misleading, anyway
[shmem]: well, previous to that << was always treated as the left-shift operator

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