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Re: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)

by Anonymous Monk
on Sep 11, 2007 at 23:25 UTC ( #638457=note: print w/ replies, xml ) Need Help??


in reply to Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)

That would be:

#!/usr/bin/env python str = "ABBBCCDDZ" parts = [] for i in range(len(str)): if len(parts)>0: if parts[len(parts)-1][len(parts[len(parts)-1])-1]==str[i]: parts[len(parts)-1] += str[i] else: parts.append(str[i]) else: parts.append(str[i]) print parts
- Antonio Ognio, Lima-Peru


Comment on Re: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)
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Re^2: Yet Another Rosetta Code Problem (Perl, Ruby, Python, Haskell, ...)
by Anonymous Monk on Sep 11, 2007 at 23:40 UTC

    Another solution, much more verbose but certainly more readable:

    #!/usr/bin/env python str = "ABBBCCDDZ" parts = [] last_char = '' current_chunk = '' for i in range(len(str)): current_char = str[i] if (current_chunk == '') or (last_char == current_char): current_chunk = current_chunk + current_char else: parts.append(current_chunk) current_chunk = current_char last_char = current_char if len(current_chunk)>0: parts.append(current_chunk) print parts

    Also available here:

    http://pastebin.com/f1213db97

    - Antonio Ognio, Lima-Peru

      I find them equivalently unreadable ;-)
      Gnah. No No and No.

      The itertools version is quite lovely, but if you must do an iterative version please at least make it idiomatic. If you really needed an index, you could at least use enumerate() ;-P

      mystr = "ABBBCCDDZ" def get_iterparts(mystr): buf = "" for char in mystr: if not buf or buf.endswith(char): buf += char else: yield buf buf = char if buf: yield buf print list(get_iterparts(mystr)) def get_parts(mystr): parts = [] buf = "" for char in mystr: if not buf or buf.endswith(char): buf += char else: parts.append(buf) buf = char if buf: parts.append(buf) return parts print get_parts(mystr)

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