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Re: Arbitrary number of captures in a regular expression

by bsb (Priest)
on Sep 25, 2007 at 10:19 UTC ( #640885=note: print w/ replies, xml ) Need Help??


in reply to Arbitrary number of captures in a regular expression

It's not fancy or general, but it's simple and may be adaptable to your purpose:

$ms = '(?: m (\d+))?' x 5; # 1) print join(",", /^foo$ms bar$/ ),"\n" for ( 'foo m 1 m 2 m 3 m 4 bar', 'foo m 2 m 4 m 7 bar', 'foo m 1 bar', ); __END__ 1,2,3,4, 2,4,7,, 1,,,,
1) Where "any number" is equal to 5...


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