Re: RegEx & Approach Question

[atemon]

in your regex $2 is

(size/max/drops/flushes).

You need to escape the parenthesis. try the code after escaping (

if ($line =~ m/\s+Input\s+queue:\s+0\/75\/(.*)\/39\s+\(size\/max\/drop
+s\/flushes\); \s+Total\s+output drops:\s+(.*)/) {

printf("%-20.20s %-22.22s : $line\n",$file,$currentInterface) if ($1 |
+| $2 != 0);

}

Note: Since ( I think ) I found some mismatch in No. of spaces from your sample text with the regex, I replaced all spaces with \s+ in the regx.

--VC

---

There are three sides to any argument.....
your side, my side and the right side.

[ikegami]

It's probably best to avoid hardcoding the other numbers.
Also, much escaping could be avoided by using an alternate delimiter.

m{\s+Input\s+queue:\s+\d+/\d+/(\d+)/\d+\s+\(size/max/drops/flushes\); 
+\s+Total\s+output drops:\s+(\d+)/