Re: Open Files in Unix

[superfrink]

in reply to Open Files in Unix

I would use something like the following command line.

find -name cynlogging.properties -exec perl -p -i.backup -e 's/search/
+replace/g' {} \;

For example:

$ mkdir x

$ cd x

$ mkdir b

$ date > asdf

$ date > b/asdf

$ cat asdf 
Wed Oct  8 13:11:35 MDT 2008

$ find . -name asdf -exec perl -p -i.backup -e 's/1/XXX/g' {} \;

$ cat asdf 
Wed Oct  8 XXX3:XXXXXX:35 MDT 2008

$ cat b/asdf 
Wed Oct  8 XXX3:XXXXXX:37 MDT 2008

$ cat asdf.backup 
Wed Oct  8 13:11:35 MDT 2008

[swartzieee]

to run as a perl script do i do system ("find -name cynlogging.properties -exec perl -p -i.backup -e 's/search/ +replace/g' {} \");

[blazar]

I personally believe that if this is a question, then it should be marked with... a question mark. Anyway, the answer is yes, or at least that is a possible way to do it. (Except that, as a minor point, you should quote the backslash.) But more importantly why, precisely, should you run the above line "as a perl script?" The whole point was that probably a single find(1) command is better suited to your need than a whole Perl program. (Although one may consider there that perl is called multiple times in the second case, and this includes a overhead... probably a completely irrelevant consideration, in this particular situation - and there are simple cures, anyway.)