Re^4: Boolean counter?

[Anonymous Monk]

$i appears only once, the behaviour is defined

$ perl -MO=Deparse,-p -le"print - --$i"
BEGIN { $/ = "\n"; $\ = "\n"; }
print((-(--$i)));
-e syntax OK

You were thinking of

print(-( ++$i - --$i ))

[ikegami]

While the operand evaluation order for the ops you've used in your example isn't defined, it doesn't matter (unless there's an overflow) for that example. It's just a clarity issue.

$i appears only once, the behaviour is defined

Except it ($Counter) appeared twice.